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Manipal MET2021MathematicsQuadratic Equation

The equation ( p-1) x^2+ p x+ p=0 in the variable x , has real roots. Then, p can take any value in the interval

Options

  1. A(0, )
  2. B(- , 0)
  3. C(- 2 , 2 )
  4. D(- , )

Correct answer

A. (0, )

Step-by-step solution

Since, the given equation has real roots. Discriminant, array cc & D= ^2 p-4( p-1) p 0 & D=( p-2 p)^2+4 p(1- p) 0 & 0 p array

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