Manipal MET2017MathematicsSequences and Series
0.2+0.22+0.222+ . to n terms is equal to
Options
- A( 2 9 )- ( 2 81 ) (1-10^ -n )
- Bn- ( 1 9 ) (1-10^ -n )
- C( 2 9 ) [n- ( 1 9 ) (1-10^ -n ) ]
- D( 2 9 )
Correct answer
C. ( 2 9 ) [n- ( 1 9 ) (1-10^ -n ) ]
Step-by-step solution
0.2+0.22+0.222+ . n terms =2(011+011+0.111+ n terms ) aligned & =2 ( 1 10 + 11 100 + 111 1000 + n terms ) & = 2 9 ( 9 10 + 99 100 + 999 1000 + n terms ) & = 2 9 (1- 1 10 +1- 1 100 +1- 1 1000 + n terms ) & = 2 9 [n- ( 1 10 + 1 100 + 1 1000 + n ) ] & = 2 9 [n- 1 10 1- ( 1 10 )^n . (1- 1 10 ) ] ] & = 2 9 [n- 1 10 10 9 ( 10^n-1 10^n ) ] & = 2 9 [n- 1 9 (1-10^ -n ) ] aligned