Manipal MET2019MathematicsStraight Lines
The distance of the line 2 x-3 y=4 from the point (1,1) measured parallel to the line x+y=1 is
Options
- A2
- B5 / 2
- C1 / 2
- D6
Correct answer
A. 2
Step-by-step solution
Given that equation of lines are 2 x-3 y=4 ...(i) and x+y=1 or x+y-1=0 ...(ii) Now, let any line parallel to x+y-1=0 is given by x+y+ =0 which passes through (1,1) . 1+1+ =0 =-2 Required line is x+y-2=0 or x+y=2 ...(iii) Point of intersection of lines (i) and (iii) is (2,0) . Required distance = (2-1)^2+(0-1)^2 = 1+1 = 2