At T(K) for one mole of an ideal gas, the graph of P (on y -axis) and V ⁻¹ (on x -axis) gave a straight line with slope of 32.8 ~L ~atm ~mol ⁻¹ . What is the temperature (in K )? ( R =0.082 ~L ~atm ⁻¹ Kol ⁻¹ )

Step-by-step solution

Ideal gas equation is aligned & PV = nRT & for 1 ~mole , & P = 1 ~V RT & Y = x m + C & m (slope) = RT & C (intercept) =0 & Slope ( m )=32.8 Latm mol ⁻¹ & RT =32.8 ~L ~atm ~mol ⁻¹ & or, T = 32.8 Latmmol ⁻¹ 0.082 atmLmol ⁻¹ ~K ⁻¹ aligned T =400 ~K