At 240.55 K , for one mole of an ideal gas, a graph of P (on y -axis) and V ⁻¹ (on x -axis) gave a straight line passing through origin. Its slope (m) is 2000 ~J ~mol ⁻¹ . What is the kinetic energy (in J mol ⁻¹ ) of ideal gas?

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Quantrex Academy · Accepted Answer

Correct answer: B. 3000

aligned & Kinetic energy ( K . E )= 3 2 PV & P = 2 KE 3 1 ~V & KE =3000 ~J ~mol ⁻¹ & Y = mX + c & m ( Slope )=2000 ~J ~mol ⁻¹ & 2 KE 3 =2000 ~J ~mol ⁻¹ aligned

At 240.55 K , for one mole of an ideal gas, a graph of P (on y -axis) and V ⁻¹ (on x -axis) gave a straight line passing through origin. Its slope (m) is 2000 ~J ~mol ⁻¹ . What is the kinetic energy (in J mol ⁻¹ ) of ideal gas?

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