At STP, a closed vessel contains 1 mole each of He and CH ₄ . Through a small hole, 2L of He and 1 L of CH ₄ was escaped from vessel in ' t ' minutes. What are the mole fractions of He and CH ₄ respectively remaining in the vessel? (Assume He and CH ₄ as ideal gases. At STP one mole of an ideal gas occupies 22.4 L of volume)

Step-by-step solution

Initial mole of He ( n ₁ )=1 Initial mole of CH ₄ ( n ₂ )=1 No. of mole of He escaped ( n ₂^ )= 2 22.4 =0.089 No. of mole of CH ₄ escaped ( n ₂^ )= 2 22.4 =0.044 Remaining no. of mole ( n ^ ₁ )= n ₁- n ₁^ aligned & =1-0.089 & =0.90 aligned Remaining no. of mole ( n ^ ₂ )=1-0.044=0.95 Mole fraction of He ( _ He )= 0.90 1.85 =0.488 Mole fraction of CH ₄ ( _ CH ₄ )= 0.95 1.85 =0.512