AP EAMCET202319 May 2023Morning ShiftChemistryStates of MatterActual
At 200 ~K , an ideal gas ( X ) present in a 1 ~L flask has a concentration of 1 ~mol ~L ⁻¹ . At the same temperature, 0.1 mole of X is added into the vessel: What is the final pressure of the gas in atm? (Given R =0.082 ~L ^ atom mol ⁻¹ ~K ⁻¹ )
Options
- A18.04
- B16.4
- C8.2
- D9.02
Correct answer
A. 18.04
Step-by-step solution
At a constant temperature, and volume, aligned & P ₁ n ₁ = P ₂ n ₂ & P ₂= P ₁ n ₁ n ₂ aligned Now, P ₁= n ₁ RT V = (1)(0.082)(200) 1 =16.4 ~atm Thus, P ₂= P ₁ n ₁ n ₂= 16.4 1 1.1 =18.04 ~atm