Manipal MET2010PhysicsElectromagnetic Waves
X-ray of wavelength =2 Å is emitted from the metal target. The potential difference applied across the cathode and the metal target is
Options
- A5525 V
- B320 V
- C6200 V
- D3250 V
Correct answer
C. 6200 V
Step-by-step solution
Potential difference aligned V & = h c e & = 6.6 10⁻³⁴ 3 10^8 1.6 10⁻¹⁹ 2 10⁻¹⁰ & =6200 volt aligned