Manipal MET2013PhysicsGravitation
Radius of orbit of satellite of earth is R . Its kinetic energy is proportional to
Options
- A1 R
- B1 R
- CR
- D1 R^ 3 / 2
Correct answer
A. 1 R
Step-by-step solution
Gravitational force provides the required centripetal force. The gravitational force provides the required centripetal force in orbit of earth. G M_e M R^2 = m v₀^2 R v₀= G M_e R kinetic energy = 1 2 m v₀^2 KE = 1 2 m ( G M_ e R )^ 2 / 2 = 1 2 m G M_e R K E 1 R