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Manipal MET2013PhysicsGravitation

Escape velocity at surface of earth is 11.2 Km / s . Escape velocity from a planet whose mass is the same as that of earth and radius 1 / 4 that of earth, is

Options

  1. A2.8 ~km / s
  2. B15.6 ~km / s
  3. C22.4 ~km / s
  4. D44.8 ~km / s

Correct answer

C. 22.4 ~km / s

Step-by-step solution

At a crtain velocity of projection the body will go out of the gravitational field of the earth and will never return to the earth, this velocity is known as escape velocity. v_ = 2 G M_e R_e Given, M_e=M_p, R_p= R_e 4 v_p v_e = M_e M_e R_e R_e / 4 = 4 =2 aligned v_ & =2 v_e=2 11.2 & =22.4 ~km / s aligned

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