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Manipal MET2011PhysicsGravitation

Escape velocity from earth's surface is 11 ~km / s . If radius of a planet is double than that of earth and density is same as that of earth, then the escape velocity from this planet will be

Options

  1. A5.5 ~km / s
  2. B11 ~km / s
  3. C16.5 ~km / s
  4. D22 ~km / s

Correct answer

D. 22 ~km / s

Step-by-step solution

Escape velocity aligned v_e & = 2 G M R & =R 8 3 G aligned v R We can say, if radius of a planet is double than that of earth then escape velocity from this planet will be 22 ~km / s .

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