Manipal MET2010PhysicsGravitation
The time period of a geostationary satellite at a height 36000 km is 24 h . A spy satellite orbits earth at a height 6400 km . What will be the time period of spy satellite? [Radius of the earth =6400 ~km ]
Options
- A5 h
- B4 h
- C3 h
- D12 h
Correct answer
B. 4 h
Step-by-step solution
From Kepler's third law of planetary motion T^2 R^3 T₂^2 T₁^2 = R₂^3 R₁^3 or T₂^2 (24)^2 = ( 6400+6400 36000+6400 )^3 or T₂^2=(24)^2 ( 16 53 )^3 T₂=4 ~h