Manipal MET2014PhysicsMathematics in Physics
A student performs an experiment for determination of g (= 4 ^2 l T^2 ), l 1 ~m , and he commits an error of l . For T he takes the time of n oscillations with the stop watch of least count T and he commits a human error of 0.1 s . For which of the following data, the measurement of g will be most accurate?
Options
- A( l =5 ~mm , ~T =0.2 ~s , n =20 ), Amplitude of oscillation (=5 ~mm )
- B( l =5 ~mm , ~T =0.1 ~s , n =20 ), Amplitude of oscillation (=1 ~mm )
- C( l =1 ~mm , ~T =0.1 ~s , n =50 ), Amplitude of oscillation (=1 ~mm )
- D( l =5 ~mm , ~T =0.2 ~s , n =10 ), Amplitude of oscillation (=5 ~mm )
Correct answer
C. ( l =1 ~mm , ~T =0.1 ~s , n =50 ), Amplitude of oscillation (=1 ~mm )
Step-by-step solution
we have to calculate the error in gravity using the formulae ( g ~g = l l + 2 t nt ) where (g= ) acceleration due to gravity ( aligned & l = length & n = number of oscillations aligned ) So, after hit and trial method we can say that with option (D ) we will get the least error.