Manipal MET2010PhysicsMotion in Two Dimensions
From an inclined plane two particles are projected with same speed at same angle , one up and other down the plane as shown in figure, which of the following statements is/are correct?
Options
- AThe time of flight of each particle is the same
- BThe particles will collide the plane with same speed
- CBoth the particles strike the plane perpendicularly
- DThe particles will collide in mid air if projected simultaneously and time of flight of each particle is less
Correct answer
A. The time of flight of each particle is the same
Step-by-step solution
Here, =2 , = Time of flight of A is, aligned T₁ & = 2 u ( - ) g & = 2 u (2 - ) g & = 2 u g aligned Time of flight of B is, T₂= 2 u g = 2 u g So, T₁=T₂ . The acceleration of both the particles is g downwards. Therefore, relative acceleration between the two is zero or relative motion between the two is uniform. The relative velocity of A w.r.t. B is towards A B , therefore collision will take place between the two in mid air.