At what temperature will the total kinetic energy of 0.30 moles of He be same as the total kinetic energy of 0.40 moles of Ar at 400 ~K ?

Step-by-step solution

Kinetic energy (KE) = 3 n R T 2 Here, n= number of moles T= temperature R= rate constant Now, kinetic energy of He = total KE of Ar Now, KE of He KE of Ar = ( mole of He ) ( temp. of He ) ( mole of Ar) ( temp. of Ar ) aligned 1 & = 0.30 T₁ 0.40 400 T₁= 0.40 400 0.30 T₁ & =533 ~K aligned Hence, at temperature 533 ~K , KE of He and Ar will be same.