A particle is projected from the ground with an initial speed of u at an angle with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is :

Step-by-step solution

Refer figure as shown, the average velocity = displacement time taken v_ av = H^2+R^2 / 4 T / 2 ...(i) Here, H= u^2 ^2 2 g R= u^2 2 g Putting these values in Eq. (i), we get v_ av = u 2 1+3 ^2