If two molecules of A and B having mass 100 ~kg and 64 ~kg and rate of diffusion of A is 12 10⁻³ , then rate of diffusion of B will be

Step-by-step solution

aligned & m_A= ( 100 2 ) kg / molecule & m_B= ( 64 2 ) kg / molecule aligned Rate of diffusion, r_B= ? r_A=12 10⁻³ According to Graham's law of diffusion, r_A r_B = d_B d_A = M_B M_A r_A r_B = m_B N_A m_A N_A (N_A= . Avogadro's number ) r_A r_B = 64 100 = 8 10 =0.8 or 12 10⁻³ r_B =0.8r_B= 12 10⁻³ 0.8 =15 10⁻³