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AP EAMCET202120 Aug 2021Evening ShiftChemistryStates of MatterActual

When the temperature of a gas is increased from 30 ° C to 930 ° C , the root mean square speed of the gas would

Options

  1. Aget doubled
  2. Bremain constant
  3. Cgets halved
  4. Dincrease by 5 . 5 times

Correct answer

A. get doubled

Step-by-step solution

Root-mean-square is directly proportional to the square root of temperature. u rms = 3 RT M At the different temperature of same gas, the mass will be same. Temperature T 1 = 30 + 273 = 303 K Temperature T 2 = 930 + 273 = 1203 K So, u 1 u 2 = T 1 T 2 = 303 1203 = 17 . 41 3 . 68 u 2 = 2 u 1 Hence, the root mean square speed of the gas would get doubled.

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