In the circuit diagram, the current through the Zener diode is

Step-by-step solution

The voltage drop across R₂ is V_ R₂ =V_z=10 ~V The current through R₂ is aligned I_ R₂ & = V_ R₂ R₂ = 10 1500 =0.667 10⁻² ~A & =6.67 10⁻³ ~A =6.67 ~mA aligned The voltage drop across R₁ is V_ R₁ =15 ~V -V_ R₂ =15 ~V -10 ~V =5 ~V The current through R₁ is I_ R₁ = V_ R₁ R₁ = 5 ~V 500 =10⁻² ~A =10 10⁻³=10 ~mA The current through Zener diode is I_z=I_ R₁ -I_ R₂ =(10-6.67) mA =3.33 ~mA