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Manipal MET2015PhysicsSemiconductors

The following configuration of gate is equivalent to

Options

  1. ANAND
  2. BXOR
  3. COR
  4. DNone of these

Correct answer

B. XOR

Step-by-step solution

Y=(A+B) A B The given output equation can also be written as Y=(A+B) ( A + B ) (Demorgan's theorem) array ll & Y=A A +A B +B A +B B & Y=0+A B + A B+0 & Y= A B+A B array This is the expression for XOR gate.

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