The molar heat capacity of rock salt at low temperature varies with temperature according to Debye's T^3 law Thus C=k T^3 ^3 where k=1940 Jmol ⁻¹ ~K ⁻¹ =281 ~K Calculate how much heat is required to raise the temperature of 2 moles of rock

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The molar heat capacity of rock salt at low temperature varies with temperature according to Debye's T^3 law Thus C=k T^3 ^3 where k=1940 Jmol ⁻¹ ~K ⁻¹ =281 ~K Calculate how much heat is required to raise the temperature of 2 moles of rock salt from 10 K to 50 K

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Correct answer: C. 273 J

aligned & d Q=n C d T & d Q=n k T^3 ^3 d T & Q= n k ^3 _ T₁ ^ T₂ T^3 d T & = n K ^3 ( T₂^4-T₁^4 4 ) & = 2 1940 (50^4-10^4 ) (281)^3 4 & =272.79 ~J =273 ~J aligned

The molar heat capacity of rock salt at low temperature varies with temperature according to Debye's T^3 law Thus C=k T^3 ^3 where k=1940 Jmol ⁻¹ ~K ⁻¹ =281 ~K Calculate how much heat is required to raise the temperature of 2 moles of rock salt from 10 K to 50 K

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