When a copper sphere is heated, percentage change is

Step-by-step solution

Let R be the radius of sphere, V its volume and its density. Then, R=R and percentage change in radius R R 100=100 ...(i) Now, V= v =3 v =3 Percentage increase in volume = V V 100=300 ...(ii) Again, ^ = 1+ = 1+3 = - ^ = [1- 1 1+3 ]= (3 ) 1+3 Percentage change in density = 100= 300 1+3 ...(iii) From Eqs. (i), (ii) and (iii), we see that the percentage change is maximum in volume.