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Manipal MET2010PhysicsThermal Properties of Matter

Three identical thermal conductors are connected as shown in figure. Considering no heat loss due to radiation, temperature at the junction will be

Options

  1. A40^ C
  2. B60^ C
  3. C50^ C
  4. D35^ C

Correct answer

C. 50^ C

Step-by-step solution

Let the temperature of junction be . In equilibrium, rate of flow of heat through rod 1 is equal to sum of rate of flow of heat through rods 2 and 3 , ie, ( d Q d t )₁= ( d Q d t )₂+ ( d Q d t )₃ K A( -20) l = K A(60- ) l + K A(70- ) l -20=130-2 aligned & or &3 =150 aligned =50^ C

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