Manipal MET2017PhysicsThermal Properties of Matter
The surface area of a black body is 5 10⁻⁴ ~m ^2 and its temperature is 727^ C . The energy radiated by it per minute is ( =5.67 10⁻⁸ ~J / m ^2- s - K ^4 )
Options
- A1.7 10^3 ~J
- B2.5 10^2 ~J
- C8 10^3 ~J
- D3 10^4 ~J
Correct answer
A. 1.7 10^3 ~J
Step-by-step solution
From Stefan's law E= T^4 A Given, T=727^ C =727+273=1000 ~K A=5 10⁻⁴ ~m ^2 Energy =5.67 10⁻⁸ (1000)^4 (5 10⁻⁴ ) 60 E=1.7 10^3 ~J