Manipal MET2012PhysicsThermodynamics
Work done by air when it expands from 50 L to 150 L at a constant pressure of 2 atmosphere is
Options
- A2 10^4 ~J
- B2 100 ~J
- C2 10¹¹ ~J
- D2 10¹⁵ ~J
Correct answer
A. 2 10^4 ~J
Step-by-step solution
Work done gathered W=p (V₂-V₁ ) Given, p=2 10^5 ~N / m ^2, V₁=50 10⁻³ ~m ^3 V₂=150 10⁻³ ~m ^3 W=2 10^5(150-50) 10⁻³ W=2 10^5 100 10⁻³ W=2 10^4 ~J gathered