Manipal MET2018PhysicsThermodynamics
Two different isotherms representing the relationship between pressure p and volume V at a given temperature of the same ideal gas are shown for masses m₁ and m₂ of the gas respectively in the figure given, then
Options
- Am₁ m₂
- Bm₁=m₂
- Cm₁ m₂
- Dm₁ m₂
Correct answer
C. m₁ m₂
Step-by-step solution
p V=n R T= m M R T For lst graph, p= m₁ M R T V₁ For 2nd graph, p= m₂ M R T V₂ Equating the two, we get array ll & m₁ m₂ = V₁ V₂ m & 1 V array As V₂ V₁ m₁ m₂