1 ~cm ^3 of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of 1671 ~cm ^3 . If the atmospheric pressure =1.013 10^5 ~N / m ^2 and the mechanical equivalent of heat =4.19 ~J / cal , the energy spent in this

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1 ~cm ^3 of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of 1671 ~cm ^3 . If the atmospheric pressure =1.013 10^5 ~N / m ^2 and the mechanical equivalent of heat =4.19 ~J / cal , the energy spent in this process in overcoming intermolecular forces is

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Correct answer: C. 500 cal

According to first law of thermodynamics aligned & & Q & = U+ W & & U & = Q- W aligned =540- p (V₂-V₁ ) J aligned & =540- 1.013 10^5 [(1671-1) 10⁻⁶ ] 4.2 & =540-40=500 cal aligned

1 ~cm ^3 of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of 1671 ~cm ^3 . If the atmospheric pressure =1.013 10^5 ~N / m ^2 and the mechanical equivalent of heat =4.19 ~J / cal , the energy spent in this process in overcoming intermolecular forces is

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