Manipal MET2014PhysicsUnits and Dimensions
The equation (p+ a V^2 )(V-b)= constant. The unit of a is
Options
- ADyne cm ^5
- BDyne cm ^4
- CDyne / cm ^3
- DDyne / cm ^2
Correct answer
B. Dyne cm ^4
Step-by-step solution
According to the principle of dimensional homogenity [p]= [ a v^2 ] . [a]=[p] V^2 ]= [M L⁻¹ T⁻² ] [L^6 ]= [M L^5 T⁻² ] Hence, the units of a= gm cm ^5 s ⁻²= Dyne cm ^4