In Young's double slit experiment, when wavelength used is 600 Å and the screen is 40 cm from the slits, then the fringes are 0.012 cm apart. What is the distance between the slits?

Step-by-step solution

Given, D=40 ~cm =40 10⁻² ~m aligned & =600 Å=6000 10⁻¹⁰ ~m W & =0.012 ~cm =0.012 10⁻² ~m aligned Fringe width, W= D d d= D W where, d= distance between the slits d= 40 10⁻² 6000 10⁻¹⁰ 0.012 10⁻² aligned & =2 10⁻³ ~m =2 ~mm & =0.2 ~cm aligned