Manipal MET2012PhysicsWaves and Sound
A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340 ~ms ⁻¹ , the distance between the cliffs is
Options
- A680 m
- B1700 m
- C340 m
- D1620 m
Correct answer
C. 340 m
Step-by-step solution
Let the distance between the two cliffs be d . Since, the man is standing midway between the two cliffs, then the distance of man from either end is d / 2 . The distance travelled by sound (in producing an echo) 2 d 2 =v t d=340 1=340 ~m