Manipal MET2021PhysicsWork, Power and Energy
The displacement x and time t for a particle are related to each other as t= x +3 . What is work done in first 6 s of its motion ?
Options
- A6 J
- BZero
- C4 J
- D2 J
Correct answer
B. Zero
Step-by-step solution
t= x +3 or x=(t-3)^2 Now, v= d x d t =2(t-3) At t=0, v₁=2(-3)=-6 At t=6, v₂=2(6-3)=6 Work done = change in KE = 1 2 m v₂^2- 1 2 m v₁^2=0