A force F=(2+x) acts on a particle in x -direction, where F is in newton and x in metre. The work done by this force during'a displacement from x=1.0 ~m to x=2.0 ~m is

Step-by-step solution

The work done in small displacement from x to x+d x is d W=F d x=(2+x) d x Hence, W= ₁^2 d W= ₁^2(2+x) d x= ₁^2 2 d x+ ₁^2 x d x= [2 x+ x^2 2 ]₁^2=3.5 ~J