A force of 20 N acts on a body of mass 2 kg initially at rest. Find the work done in 2 s .

Step-by-step solution

F= d p d t p=F d t where p= momentum =m v m v=F d t v= F d t m Given, F=20 ~N , d t=2 ~s , m=2 ~kg v= 20 2 2 =20 ~m / s ^2 Work done = KE = 1 2 2 (20)^2=400 ~J