When a spring is stretched by 2 cm , it stores 100 J of energy. If it is stretched further by 2 cm , the stored energy will be increased by

Step-by-step solution

Ist case, aligned U & = 1 2 k x₁^2 100 & = 1 2 k (2 10⁻² )^2 k & = 200 4 10⁻⁴ & =50 10^4 aligned IInd case aligned U & = 1 2 k x₂^2 & = 1 2 50 10^4 (4 10⁻² )^2 & =25 10^4 16 10⁻⁴ & =400 ~J aligned So, stored energy increases by 400-100=300 ~J