Find the structure of A in following reaction

Step-by-step solution

The given reaction is the acid-catalyzed hydration of an alkene. The electrophile H^+ from the acid attacks the double bond of 1-methylcyclohexene. According to Markovnikov's rule, protonation occurs at the less substituted carbon (C2) to form the more stable tertiary carbocation at the C1 position (1-methylcyclohexyl cation). A water molecule acts as a nucleophile and attacks the tertiary carbocation, forming an oxonium ion intermediate. Deprotonation of the oxonium ion yields the final product, 1-methylcyclohexan