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MHT CET202521 Apr 2025Evening ShiftChemistryAlcohols Phenols and EthersActual

Methyl propanoate on hydrolysis with dil NaOH forms a salt that on further acidification with conc. HCl forms

Correct answer

2

Step-by-step solution

Methyl propanoate, CH₃ CH₂ COOCH₃ , undergoes base hydrolysis with dilute NaOH to form sodium propanoate and methanol: CH₃ CH₂ COOCH₃ + NaOH CH₃ CH₂ COONa + CH₃ OH . Treatment of sodium propanoate with concentrated HCl yields propanoic acid: CH₃ CH₂ COONa + HCl CH₃ CH₂ COOH + NaCl . Comparing the product with the options: A is acetic acid, B is ethyl formate, C is propanoic acid ( CH₃ CH₂ COOH ), and D is ethyl acetate. The correct answer is C .

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