If the kinetic energy and RMS speed of a gas at a certain temperature are 4 . 0 kJ mol - 1 and 5 . 0 × 10 4 cm s - 1 , respectively. The molecular weight of the gas is

Step-by-step solution

As the kinetic energy expression used the RMS speed of the gas as: 1 2 Mv 2 rms = 5 . 0 × 10 4 1 2 M ( 5 . 0 × 10 4 × 10 - 2 ) 2 rms = 4 × 10 3 M = 0 . 032   Kg   mole - 1 Therefore, molecular weight is 0 . 032   Kg   per   mole   or   32   g   per   mole .