If the kinetic energy of ( O ₂ ) gas is (4.0 ~kJ ~mol ⁻¹ ), its RMS speed in ( cm s ⁻¹ ) is

Step-by-step solution

Kinetic energy of ( O ₂=4.0 ~kJ / mol ) ( aligned KE & = 3 R T 2 and v_ rms = 3 R T M v_ rms & = 2 KE M & = 2 4 10^3 ~kg ~m ^2 ~s ⁻² ~mol ⁻¹ 32 10⁻³ ~kg ~mol ⁻¹ aligned ) ( aligned & [ 1 ~J =1 ~kg ~m ^2 ~s ⁻² ] = & 10^3 2 =5 10^2 ~m / s aligned ) (v_ rms ) in ( cm / s =50 10^4 ~cm / s )