AP EAMCET201822 Apr 2018Evening ShiftChemistryStates of MatterActual
The temperature of 4.0 moles of a gas occupying 5 dm ^3 at 3.32 bar is (R=0.083 bar dm ^3 ~K ⁻¹ ~mol ⁻¹ )
Options
- A25 K
- B50 K
- C75 K
- D100 K
Correct answer
B. 50 K
Step-by-step solution
The amount of the gas, n=4.0 ~mol Volume of gas Y=5 dm ^3 Pressure of the gas p=3.32 bar R=0.083 bar dm ^3 ~K ⁻¹ ~mol ⁻¹ From the ideal gas equation, we get p V=n R T T= p V n R =(3 32 5) /(4 0 083) Hence, required temperature is =50 ~K