At 27^ C in a 10 ~L flask 4.0 ~g of an ideal gaseous mixture containing. He (molar mass 4.0 ~g ~mol ⁻¹ ) and Ne (molar mass .20 ~g ~mol ⁻¹ ) has a pres sure of 1.23 ~atm . What is the mass % of neon ? (R=0.082 ~L ~atm ~K ⁻¹ ~mol ⁻¹ )

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Correct answer: B. 62.5

Given aligned & T=27+273=300 K & V=10 L aligned aligned & Molar mass ( He )=4 & Molar mass ( Ne )=20 & P=123 ~atm & R=0.082 ~L atm K K ⁻¹ ~mol ⁻¹ aligned aligned & (i) P V= (n₁+n₂ ) R T= [ W₁ 4 + W₂ 20 ] R T & [ W₁ 4 + W₂ 20 ]= 1.23 10 0.082 300 =0.5 & 25 W₁+5 W₂=50 aligned On solving equation (ii) with the help of eq. (i) aligned & 5 W₁+4-W₁=10 W₁=1.5 & W₂=2.5 & Mass % of neon = 2.5 100 4 =62.5 % aligned

At 27^ C in a 10 ~L flask 4.0 ~g of an ideal gaseous mixture containing. He (molar mass 4.0 ~g ~mol ⁻¹ ) and Ne (molar mass .20 ~g ~mol ⁻¹ ) has a pres sure of 1.23 ~atm . What is the mass % of neon ? (R=0.082 ~L ~atm ~K ⁻¹ ~mol ⁻¹ )

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