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MHT CET202619 April 2026Morning ShiftChemistryAminesActual

Which from following compounds is obtained when propionamide is treated with Br ₂ and concentrated aqueous KOH solution ?

Options

  1. ACH ₃ CH ₂ CH ₂ COOH
  2. BCH ₃ COCH ₃
  3. CCH ₃ CH ₂ NH ₂
  4. DCH ₃ CH ₂ Br

Correct answer

C. CH ₃ CH ₂ NH ₂

Step-by-step solution

Propionamide is CH ₃ CH ₂ CONH ₂ . The reaction of an amide with Br ₂ and concentrated aqueous KOH is known as the Hoffmann bromamide degradation reaction. In this reaction, the amide is converted into a primary amine with one carbon atom less than the parent amide. CH ₃ CH ₂ CONH ₂ + Br ₂ + 4 KOH CH ₃ CH ₂ NH ₂ + K ₂ CO ₃ + 2 KBr + 2 H ₂ O The product obtained is ethylamine ( CH ₃ CH ₂ NH ₂ ). Answer: CH ₃ CH ₂ NH ₂

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