What is the number of moles of hydrogen atoms needed to obtain one mole ethanamine from acetamide using LiAl H ₄ /ether as reducing agent.

Step-by-step solution

The chemical reaction for the reduction of acetamide to ethanamine using LiAlH ₄ is: CH ₃ CONH ₂ + 4[ H ] LiAlH ₄/ ether CH ₃ CH ₂ NH ₂ + H ₂ O In this process, the carbonyl oxygen is removed as a water molecule, which consumes two hydrogen atoms. The carbonyl carbon is reduced to a methylene group ( CH ₂ ), which consumes another two hydrogen atoms. Thus, a total of 4 moles of hydrogen atoms are required to reduce one mole of acetamide to one mole of ethanamine. Answer: 4