Which from following amines when heated with ethanolic KOH and chloroform forms aryl isocyanide ?

Step-by-step solution

The reaction of an amine with chloroform and ethanolic KOH to form an isocyanide is known as the carbylamine reaction. This reaction is a characteristic test given only by primary aliphatic and primary aromatic amines. Among the given options, benzenamine (aniline) is a primary aromatic amine, while N-methylaniline and ethylethanamine are secondary amines, and N,N-dimethylaniline is a tertiary amine. Therefore, benzenamine reacts with chloroform and ethanolic KOH to form phenyl isocyanide (an aryl isocyanide). C₆H₅