MHT CET202615 April 2026Morning ShiftChemistryAminesActual
Identify the product 'B' in the following reaction CH ₃ - I KCN A Na/C ₂ H ₅ OH B
Options
- ACH ₃ -CH ₂ -CN
- BCH ₃ -CH ₂ -CH ₃
- CCH ₃ -CH ₂ -NH ₂
- DCH ₃ -NH-C ₂ H ₅
Correct answer
C. CH ₃ -CH ₂ -NH ₂
Step-by-step solution
Methyl iodide reacts with potassium cyanide to undergo nucleophilic substitution, forming methyl cyanide (acetonitrile) as product A. CH ₃ I + KCN CH ₃ CN (A) + KI Methyl cyanide undergoes Mendius reduction in the presence of sodium and ethanol to form ethylamine as product B. CH ₃ CN + 4[ H ] Na/C ₂ H ₅ OH CH ₃ CH ₂ NH ₂ (B) Thus, product B is CH ₃ -CH ₂ -NH ₂ . Answer: CH ₃ -CH ₂ -NH ₂