Which of the following is Hofmann exhaustive alkylation?

Step-by-step solution

Hofmann exhaustive alkylation describes the reaction of an amine with excess alkyl halide to form a quaternary ammonium salt through successive alkylation steps. Option A shows Hofmann bromamide degradation, converting an amide to a primary amine with one less carbon. Option C depicts Hofmann elimination, decomposing a quaternary ammonium salt to form an alkene and tertiary amine. Option D represents nitrile reduction to a primary amine (Mendius reduction). Option B corresponds exactly to Hofmann exhaustive alkylat