What is the number of moles of hydrogen atoms required to reduce one mole of nitroethane completely using Sn and HCl ?

Step-by-step solution

Reduction of nitroethane to ethylamine requires hydrogen atoms as reducing agents. The balanced equation illustrates the stoichiometry: CH₃ CH₂ NO₂ + 6[H] CH₃ CH₂ NH₂ + 2H₂ O The coefficient confirms 6 moles of hydrogen atoms are needed per mole of nitroethane. An oxidation state analysis supports this. In CH₃ CH₂ NO₂ , nitrogen is +5, while in CH₃ CH₂ NH₂ , it is −1. The 6-electron reduction corresponds to 6 atoms of hydrogen. Therefore, the required number is D .