If the position of the electron was measured with an accuracy of +0.002 nm . the uncertainty in the momentum of it would be (in . kg ms ⁻¹ ) ( h =6.626 10⁻³⁴ ~J ~s )

Step-by-step solution

Heisenberg uncertainty principle, x p= h 4 aligned & x =2 10⁻³ ~nm & x =2 10⁻³ 10⁻⁹ ~m [1 ~nm =10⁻⁹ ~m ] & x =2 10⁻¹² ~m & ~h =6.626 10⁻³⁴ Js & [1 ~J =1 ~kg ~m ^2 ~s ⁻² ] & x p= 1 4 & p = h 4 . x = 6.626 10⁻³⁴ Js 4 3.14 2 10⁻¹² ~m & =0.2637 10⁻²² ~kg ~ms ⁻¹ & =2.637 10⁻²³ ~kg ~ms ⁻¹ aligned