In the ground state of hydrogen atom. electron absorbs 1.5 times energy than the minimum energy (2.18 10⁻¹⁸ ~J ) to escape from the atom. The wavelength of the emitted electron (in m) is (m_e=9 10⁻³¹ ~kg )

Step-by-step solution

Energy absorbed by the element aligned & =1.5 2.18 10⁻¹⁸ ~J & =1.5 2.18 10⁻¹⁸ kgm ^2 ~s ~s ⁻² & =3.27 10⁻¹⁸ ~kg ~m ^2 ~s ⁻² aligned Energy required =2.18 10⁻¹⁸ ~J Kinetic energy of the emitted electron aligned & = Energy absorbed - energy required & = (3.27 10⁻¹⁸-2.18 10⁻¹⁸ ) kg ~m ^2 ~s ⁻² & KE =1.09 10⁻¹⁸ ~kg ~m ^2 ~s ⁻² & ~m _ e =9 10⁻³¹ ~kg aligned According to de Broglie equation = h ~m v KE = 1 2 ~m v^2 aligned & v= ( 2 KE ~m )^ 1 / 2 & = h 2 mK E aligned or, = h 2 9 10⁻³¹ ~kg 1.09 10⁻¹⁸ ~kg ~m ^2 ~s ⁻² or, =