The de Broglie wavelength of a particle of mass 1 mg moving with a velocity of 10 ~ms ⁻¹ is ( h=6.63 10⁻³⁴ ~J ~s )

Step-by-step solution

According to de Broglie wavelength ( )= h p or, = h mv [ . Where h = Plank's constant =6.63 10⁻³⁴ ~J s = momentum m = mass of moving particle v = velocity ] [1 ~J = kg m ^2 ~s ⁻² 1 mg =10⁻³ ~g 1 ~kg =10^3 ~g ] = 6.63 10⁻³⁴ ~J . s 1 mg 10 ~ms ⁻¹ aligned & = 6.63 10⁻³⁴ ~kg ~m ^2- s ⁻² ~s 10⁻³ mg 10 ~ms ⁻¹ & = 6.63 10⁻³⁴ 10^3 gm ^2 ~s ⁻¹ 10⁻² ~g ~ms ⁻¹ aligned aligned & =6.63 10⁻³⁴ 10^3 10^2 ~m & =6.63 10⁻²⁹ ~m aligned