AP EAMCET202318 May 2023Morning ShiftChemistryStructure of AtomActual
The de' Broglie wavelength of a particle is 1000 ~nm . What is its momentum? ( h =6.6 10⁻³⁴ ~J ~s )
Options
- A6.6 10⁻²⁵ ~J ~s ~m ⁻¹
- B6.6 10⁻²⁵ ~J ~s ~m
- C6.6 10⁻²⁸ ~J ~s ~m ⁻¹
- D6.6 10⁻²⁶ ~J ~s ~m
Correct answer
C. 6.6 10⁻²⁸ ~J ~s ~m ⁻¹
Step-by-step solution
=1000 ~nm =1000 10⁻⁹ ~m =1.0 10⁻⁶ ~m P= h = 6.626 10⁻³⁴ 1.0 10⁻⁶ =6.626 10⁻²⁸ ~J ~s ~m ⁻¹